4v^2+36v-88=0

Solution for 4v^2+36v-88=0 equation:

4v^2+36v-88=0

a = 4; b = 36; c = -88;
Δ = b2-4ac
Δ = 362-4·4·(-88)
Δ = 2704
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{2704}=52$
$v_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(36)-52}{2*4}=\frac{-88}{8}
=-11
$
$v_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(36)+52}{2*4}=\frac{16}{8}
=2
$